Determine the equivalent resistance of the circuit shown in the figure. PLEASE HELP!?

a) Determine the equivalent resistance of the circuit displayed in the figure.

You are watching: Find the equivalent resistance of the circuit shown in the figure.

b Determine the voltage throughout 820 Ω resistor.

c) Determine the voltage throughout 960 Ω resistor.

d) Determine the voltage throughout 680 Ω resistor.

Relative to the battery, the 820 and 680 resistors integrate in parallel to create a smaller sized resistor so

(1/820) + (1/680) = (1/R1)

1/371.7333 ohms = 1/R1

R1 = 371.7 ohms

R1 and R2 are in series so

Rt = 371.7 + 960 = 1331.7 ohms = tantamount or full resistance

To uncover voltage throughout the resistors, you"re initially going to need the present in the circuit.

V = IR

I = Vt/Rt = 12 V/1331.7 ohms = 9.0110E-3 A

You deserve to recognize voltage making use of V = IR

so start via R1 (note that given that the two resistors to the left are in parallel, they will certainly share voltage V1 which = IR1)

V1 = (9.0110E-3 A) (371.7 ohms) = 3.3493 volts

from right here you can say voltage on the 960 resistor is 12 - 3.3493 = 8.6507 volts however I"m going to calculate simply to be safe

V2 = (9.0110E-3 A) (960 ohms) = 8.65056--cshed enough, lol

a) 1331.7 ohms

b) 3.3493 volts

c) 8.6507 volts just to remain consistent with the R1

d) 3.3493 volts

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answeredMay 14by sudheer

Mastering Physics Giancoli

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