Vector Analysis: A Text-book for the Use of Students of Mathematics & Physics: Founded Upon the Lectures of J. W. GibbsScribner, 1901 - 436 sivua |
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Yleiset termit ja lausekkeet
a b c a₁ a₂ angle angular velocity antecedents axes axis b₁ b₂ c₁ c₂ center of gravity collinear components consequently constant coördinates coplanar cosine curl definition denoted derivative differential direction distributive law divergence dv₂ dyadic dyads ellipsoid equal expressed in terms finite force formulæ function of position given Hence line integral linear magnitude multiplied negative normal obtained operator origin parallel parallelogram perpendicular plane position in space potential quantity radius vector ratio reciprocal system region rotation scalar coefficients scalar function scalar product scalar triple product sides sphere surface integral tangent terminus tetrahedron theorem three non-coplanar vectors three vectors tion triangle unit vector V₁ v₂ vanishes vector drawn vector function vector product versor zero ат дх
Suositut otteet
Sivu 79 - A cos 6 = cos a cos c + sin a sin c cos B cos c = cos a cos 6 + sin a sin 6 cos C Law of Cosines for Angles cos A = — cos B...
Sivu 113 - The perpendicular bisectors of the sides of a triangle meet in a point. 12. The bisectors of the angles of a triangle meet in a point. 13. The tangents to a circle from an external point are equal. 14...
Sivu 109 - B is defined as the product of the magnitudes of A and B and the sine of the angle between them. The direction of the vector...
Sivu 60 - The sum of the squares of the diagonals of a parallelogram is equal to the sum of the squares of its four Dem.— Let ABCD be the a.
Sivu 33 - If a line be drawn parallel to the base of a triangle, it will divide, the.
Sivu 106 - The perpendiculars from the vertices of a triangle to the opposite sides meet in a point. Let the Js be AH, BP, and CK. Through A, B, C suppose B'C', A'C', A'B', drawn II to BC, AC, AB, respectively. Then AH is _L to B'C'. (Why ?) Now ABCB' and A CBC' are EJ (why ?) , and AB' = BC, and AC' = BC. (Why ?) That is, A is the middle point of B'C'.
Sivu 92 - The moment of a force f about the point 0 is equal to the product of the force by the perpendicular distance from 0 to the line of action of the force.
Sivu 53 - ... and surfaces of the second and third orders are also there founded upon the composition of vectors. EXAMPLES TO CHAPTER I. 1. The lines which join, towards the same parts, the extremities of two equal and parallel lines are themselves equal and parallel. (Euclid, I. xxxiii.) 2. Find the vector of the middle point of the line which joins the middle points of the diagonals of any quadrilateral, plane or gauche, the vectors of the corners being given ; and so prove that this point is the mean point...
Sivu 347 - ... out the economy of using one half-prism attached to the collimator with one face perpendicular to the axis, and another similar half-prism attached in a similar way to the telescope. A beam of light can thus be used larger, in proportion to the size of the face of the prism, than when a single prism with an angle equal to the sum of the angles of the half-prisms is used. Thollon has given a mathematical investigation to...
Sivu iii - University, a series of volumes has been prepared by a number of the Professors and Instructors, to be issued in connection with the Bicentennial Anniversary, as a partial indication of the character of the studies in which the University teachers are engaged.