 | John Playfair - 1806 - 320 sivua
...right angle BAG ; the square described upon the side BC is equal to the squares described upon BA, AC. On BC describe* the square BDEC, and on BA, AC the squares GB, HC ; and through A drawb AL parallel to BD or CE, and join AD, FC ; then, because each of the angles d... | |
 | Euclides - 1814 - 560 sivua
...angle BAC; the square described upon the side BC is equal to the squares described upon BA, AC. 46. i. On BC describe' the square BDEC, and on BA, AC the squares GB, HC; and through A draw b AL parallel to BD, Boo* T. or CE, and join AD, FC. Then, because each of the angles... | |
 | John Martin Frederick Wright - 1827 - 344 sivua
...C, the square described upon the side I.IC is equal to the squares described upon the sides BA, AC. On BC describe the square BDEC, and on BA, AC the...to DE — no, I mean parallel to BD or CE, and join AD, FC."-~" Very well again, Sir. Now for the Demonstration."—" Because each of the angles BAC, SAG,... | |
 | John Radford Young - 1827 - 228 sivua
...triangle BAG ; the square described upon the side BC is equivalent to the squares described upon BA, AC. On BC describe the square BDEC, and on BA, AC the squares GB, HC; and through A draw AL parallel to BD or CB; join AD, FC : then, because each of the angles BAC, BAG... | |
 | Robert Simson - 1827 - 546 sivua
...angle BAC : the square described upon the side BC shall be equal to the squares described upon BA, AC. On BC describe* the square BDEC, and on BA, AC the squares GB, HC; and through A draw* AL parallel to BD, or CE, and join AD, FC. Then, because the angle BAC is af right... | |
 | John Martin Frederick Wright - 1827 - 344 sivua
...C, the square described upon the side 11C. is equal to the squares described upon the sides BA, AC. On BC describe the square BDEC, and on BA, AC the squares GB, HC—upon my word, Sir, I forget the next step, but let me consider"— (looking at the book in his... | |
 | John Playfair - 1835 - 336 sivua
...right angle BAC ; the square described upon the side BC is equal to the squares described upon BA, AC. On BC describe the square BDEC, and on BA, AC the squares GB, HC ; and through A draw AL parallel to BD or CE, and join AD, FC ; then, because each of the angles BAC,... | |
 | Euclides - 1838 - 264 sivua
...: the square described upon the side BC shall be equal to the squares described upon BA, AC. «46 , On BC describe the* square BDEC, and on BA, AC the squares GB, HC ; and through A draw* *3'• 1• AL parallel to BD, or CE : draw also AD, FC. Then, because the angle... | |
 | Euclides - 1841 - 378 sivua
...Let ABC be a right-angled triangle having the BC shall be equal to the squares described upon BA, AC. On BC describe* the square BDEC, and on BA, AC the squares GB, HC; and through A draw* AL parallel to BD, or CE, and join AD, FC; then, because each of the angles BAC,... | |
 | Euclides - 1852 - 152 sivua
...BAG; the square described upon the side BC is equal to the squares described upon BA, AC. • xlvi. i. On BC describe* the square BDEC, and on BA, AC the squares GB, HC ; b xxxi. i. and through A draw b AL parallel to BD, or CE, and join AD, FC; Then, because each of... | |
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FC; then, because each of the angles BAC, BAG is a right angle*, the two straight lines AC, AG upon the opposite sides of AB, make with it at the point A the adjacent angles equal to two right angles; therefore CA is in the same straight line... 
