 | Woolwich roy. military acad, Walter Ferrier Austin - 1880 - 190 sivua
...triangle be produced, the exterior angle is equal to the two interior and opposite angles ; and the three interior angles of every triangle are together equal to two right angles. A is the greatest angle of a triangle ABC ; show how to divide A into two parts whose difference is... | |
 | Herbert Spencer - 1881 - 756 sivua
...triangle be produced, the exterior angle is equal to the two interior and opposite angles ; and the three interior angles of every triangle are together equal to two right angles. " Let ABC be a triangle, and let one of its sides BC be produced to D ; then the exterior angle ACD... | |
 | Francis Chilton Young - 1881 - 842 sivua
...four angles at F) which is 22° 30', being the fourth part of a right angle or 90". Then, as the three interior angles of every triangle are together equal to two right angles or 180°, the angles FAB, FBA, must be together equal to 180°— 22° 30', or 157° 30', and as these... | |
 | John Gibson - 1881 - 64 sivua
...another. 4. Through a given point draw a straight line parallel to a given straight line. 5. The three interior angles of every triangle are together equal to two right angles. 6. If the straight line bisecting the exterior angle of a triangle be parallel to the base, prove that... | |
 | John Gibson - 1881 - 302 sivua
...triangle be produced, the exterior angle is equal to the two interior and opposite angles ; and the three interior angles of every triangle are together equal to two right angles. 5. Describe a parallelogram that shall be equal to a given triangle LMN, and have one of its angles... | |
 | 1882 - 676 sivua
...produced to meet in A, B, C, D, E, and F. Then ACE, FBD form two triangles cutting each other. Now the interior angles of every triangle are together equal to two right angles, therefore the angles at A, c- E' F' B' Dl are together equal to four right angles because they are... | |
 | College of preceptors - 1882 - 528 sivua
...triangle ABO is bisected by Bit, which cuts the base in D ; prove that BO is greater than GD. 4. The three interior angles of every triangle are together equal to two right angles. Enunciate the two corollaries of this Proposition, but give the proof of the second corollary only.... | |
 | Free Church of Scotland. College Committee - 1882 - 142 sivua
...triangle be produced, the exterior angle is equal to the two interior and opposite angles ; and the three interior angles of every triangle are together equal to two right angles. 3. The complements of the parallelograms which are about the diameter of any parallelogram are equal... | |
 | Marianne Nops - 1882 - 278 sivua
...produced (1) the exterior angle is equal to the two interior and opposite angles, (2) and the three interior angles of every triangle are together equal to two right angles. I. To show that the exterior angle = 2 int. and opposite. Draw CE || to AB. Proof.— AC falls on ||s... | |
 | Herbert Spencer - 1882 - 722 sivua
...triangle be produced, the exterior angle is equal to the two interior and opposite angles ; and the three interior angles of every triangle are together equal to two right angles. " Let ABC be a triangle, and let one of its sides BC be produced to D ; then the exterior angle ACD... | |
| |
If a side of any triangle be produced, the exterior angle is equal to the two interior and opposite angles; and the three interior angles of every triangle are together equal to two right angles. 
