 The perpendiculars from the vertices of a triangle to the opposite sides meet in a point. Let the Js be AH, BP, and CK. Through A, B, C suppose B'C', A'C', A'B', drawn II to BC, AC, AB, respectively. Then AH is _L to B'C'. (Why ?) Now ABCB' and A CBC'...  Vector Analysis: A Text-book for the Use of Students of Mathematics ... - Sivu 106tekijä(t) Edwin Bidwell Wilson, Josiah Willard Gibbs - 1901 - 436 sivuaKoko teos - Tietoja tästä kirjasta
 | George Albert Wentworth - 1899 - 498 sivua
...Hence, 0 is equidistant from B and C, and B t. therefore is in the _L bisector FF'. (Why ?) Ex. 26. The perpendiculars from the vertices of a triangle to the opposite sides meet in a point. Let the Js be AH, BP, and CK. Through A, B, C suppose B'C', A'C', A'B', drawn II to BC, AC, AB, respectively.... | |
 | George Albert Wentworth - 1899 - 500 sivua
...and B. Hence, 0 is equidistant from B and C, and therefore is in the _L bisector FF'. (Why ?) Ex. 26. The perpendiculars from the vertices of a triangle to the opposite sides meet in a point. , A _, Let the Js be AH, BP, and CK. Through A, B, C suppose B'C', A'C', A'R, drawn II to BC, AC, AB,... | |
 | Webster Wells - 1899 - 424 sivua
...interior angles of a parallelogram form a rectangle. RECTILINEAR FIGURES. 63 PROP. LI. THEOREM. 138. The perpendiculars from the vertices of a triangle to the opposite sides intersect at a common point. Given AD, BE, and CFfhe Js from the vertices of A ABC to the opposite... | |
 | Wooster Woodruff Beman, David Eugene Smith - 1899 - 416 sivua
...case of prop. XXXI : The perpendicular bisectors of the sides of a triangle are concurrent. 510. Also, the perpendiculars from the vertices of a triangle to the opposite sides are concurrent. 511. If three circumferences intersect in pairs, the common chords are concurrent.... | |
 | William James Milne - 1899 - 396 sivua
...from the vertices perpendicular to the opposite sides. Do these lines intersect in a point? Theorem. The perpendiculars from the vertices of a triangle to the opposite sides pass through the same point. H c Data: Any triangle, as ABC, and the lines AD, BE, and CF drawn from... | |
 | Wooster Woodruff Beman, David Eugene Smith - 1899 - 272 sivua
...and b, Prop. XLII .'. P1 lies on CT. Similarly for P , . Prop. XLII PROPOSITION XLV. 133. Theorem. The perpendiculars from the vertices of a triangle to the opposite sides are concurrent. Given the A ABC. To prove that the perpendiculars from A, B, C, to a, b, c, respectively,... | |
 | New York (State). Department of Public Instruction - 1900 - 1314 sivua
...examples of two of them. 2 Give two theorems upon the equality of triangles, and prove your second. S The perpendiculars from the vertices of a triangle to the opposite sides meet in a 682 Department of Public Instruction 6 Prove that two triangles are similar when the sides of one are... | |
 | 1902 - 132 sivua
...picture plane. SPa will be vertically in line with SPr at a distance from HPP equal to rs. 133. — Since the perpendiculars from the vertices of a triangle to the opposite sides meet in a common point, it is evident that any three points may represent the vanishing points of three systems... | |
 | Joseph Battell - 1903 - 722 sivua
...with the diagonal, makes an isosceles triangle, of which half of the other diagonal is the altitude. 'The perpendiculars from the vertices of a triangle to the opposite sides meet in a point.' M "This is only true in an acute or right angle triangle, unless the perpendiculars are extended. XLIX.... | |
 | George Albert Wentworth - 1904 - 496 sivua
...B. Hence, 0 is equidistant from B and C, and B therefore is in the J- bisector FF'. (Why ?) Ex. 26. The perpendiculars from the vertices of a triangle to the opposite sides meet in a point. • A Let the -ls be AH, BP, and CK. Through A, B, C suppose B'C', A'C', A'B', drawn II to BC, AC,... | |
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